(3x+5)(x^2-x-12)=0

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Solution for (3x+5)(x^2-x-12)=0 equation: 


Simplifying
(3x + 5)(x2 + -1x + -12) = 0

Reorder the terms:
(5 + 3x)(x2 + -1x + -12) = 0

Reorder the terms:
(5 + 3x)(-12 + -1x + x2) = 0

Multiply (5 + 3x) * (-12 + -1x + x2)
(5(-12 + -1x + x2) + 3x * (-12 + -1x + x2)) = 0
((-12 * 5 + -1x * 5 + x2 * 5) + 3x * (-12 + -1x + x2)) = 0
((-60 + -5x + 5x2) + 3x * (-12 + -1x + x2)) = 0
(-60 + -5x + 5x2 + (-12 * 3x + -1x * 3x + x2 * 3x)) = 0
(-60 + -5x + 5x2 + (-36x + -3x2 + 3x3)) = 0

Reorder the terms:
(-60 + -5x + -36x + 5x2 + -3x2 + 3x3) = 0

Combine like terms: -5x + -36x = -41x
(-60 + -41x + 5x2 + -3x2 + 3x3) = 0

Combine like terms: 5x2 + -3x2 = 2x2
(-60 + -41x + 2x2 + 3x3) = 0

Solving
-60 + -41x + 2x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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